132340144102433 has 4 divisors (see below), whose sum is σ = 132404293471488. Its totient is φ = 132275994733380.

The previous prime is 132340144102391. The next prime is 132340144102451. The reversal of 132340144102433 is 334201441043231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132340144102433 - 2¹⁰ = 132340144101409 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132340144102393 and 132340144102402.

It is not an unprimeable number, because it can be changed into a prime (132340194102433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 32074681433 + ... + 32074685558.

It is an arithmetic number, because the mean of its divisors is an integer number (33101073367872).

Almost surely, 2^{132340144102433} is an apocalyptic number.

It is an amenable number.

132340144102433 is a deficient number, since it is larger than the sum of its proper divisors (64149369055).

132340144102433 is an equidigital number, since it uses as much as digits as its factorization.

132340144102433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 64149369054.

The product of its (nonzero) digits is 82944, while the sum is 35.

Adding to 132340144102433 its reverse (334201441043231), we get a palindrome (466541585145664).

The spelling of 132340144102433 in words is "one hundred thirty-two trillion, three hundred forty billion, one hundred forty-four million, one hundred two thousand, four hundred thirty-three".