Base | Representation |
---|---|
bin | 11110000110000111101111… |
… | …011000101111001001101011 |
3 | 122100122200111222202100021120 |
4 | 132012013233120233021223 |
5 | 114322104410442300133 |
6 | 1145302135112510323 |
7 | 36610561221301323 |
oct | 3606075730571153 |
9 | 570580458670246 |
10 | 132362023400043 |
11 | 391a14675a1808 |
12 | 12a187919ab3a3 |
13 | 58b18ba653568 |
14 | 24984db270283 |
15 | 104808ee1dab3 |
hex | 7861ef62f26b |
132362023400043 has 4 divisors (see below), whose sum is σ = 176482697866728. Its totient is φ = 88241348933360.
The previous prime is 132362023400029. The next prime is 132362023400059. The reversal of 132362023400043 is 340004320263231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132362023400043 - 214 = 132362023383659 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 132362023399977 and 132362023400013.
It is not an unprimeable number, because it can be changed into a prime (132362023400083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22060337233338 + ... + 22060337233343.
It is an arithmetic number, because the mean of its divisors is an integer number (44120674466682).
Almost surely, 2132362023400043 is an apocalyptic number.
132362023400043 is a deficient number, since it is larger than the sum of its proper divisors (44120674466685).
132362023400043 is an equidigital number, since it uses as much as digits as its factorization.
132362023400043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44120674466684.
The product of its (nonzero) digits is 62208, while the sum is 33.
Adding to 132362023400043 its reverse (340004320263231), we get a palindrome (472366343663274).
The spelling of 132362023400043 in words is "one hundred thirty-two trillion, three hundred sixty-two billion, twenty-three million, four hundred thousand, forty-three".
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