13240113 has 4 divisors (see below), whose sum is σ = 17653488. Its totient is φ = 8826740.

The previous prime is 13240109. The next prime is 13240141. The reversal of 13240113 is 31104231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31104231 = 3 ⋅10368077.

It is a cyclic number.

It is not a de Polignac number, because 13240113 - 2² = 13240109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13240092 and 13240101.

It is not an unprimeable number, because it can be changed into a prime (13240103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2206683 + ... + 2206688.

It is an arithmetic number, because the mean of its divisors is an integer number (4413372).

Almost surely, 2^13240113 is an apocalyptic number.

It is an amenable number.

13240113 is a deficient number, since it is larger than the sum of its proper divisors (4413375).

13240113 is an equidigital number, since it uses as much as digits as its factorization.

13240113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4413374.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 13240113 is about 3638.6966073032. The cubic root of 13240113 is about 236.5723027447.

Adding to 13240113 its reverse (31104231), we get a palindrome (44344344).

The spelling of 13240113 in words is "thirteen million, two hundred forty thousand, one hundred thirteen".