Base | Representation |
---|---|
bin | 11110000110101100111110… |
… | …011100001001011110000011 |
3 | 122100210111201100001120121212 |
4 | 132012230332130021132003 |
5 | 114323233301111300003 |
6 | 1145332350252240335 |
7 | 36613505045216402 |
oct | 3606547634113603 |
9 | 570714640046555 |
10 | 132402004400003 |
11 | 39207413852838 |
12 | 12a2448b4700ab |
13 | 58b55bc7b28a0 |
14 | 249a4110d3639 |
15 | 104912ee00dd8 |
hex | 786b3e709783 |
132402004400003 has 4 divisors (see below), whose sum is σ = 142586773969248. Its totient is φ = 122217234830760.
The previous prime is 132402004399981. The next prime is 132402004400033. The reversal of 132402004400003 is 300004400204231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132402004400003 - 26 = 132402004399939 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132402004400033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5092384784603 + ... + 5092384784628.
It is an arithmetic number, because the mean of its divisors is an integer number (35646693492312).
Almost surely, 2132402004400003 is an apocalyptic number.
132402004400003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
132402004400003 is a deficient number, since it is larger than the sum of its proper divisors (10184769569245).
132402004400003 is a wasteful number, since it uses less digits than its factorization.
132402004400003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10184769569244.
The product of its (nonzero) digits is 2304, while the sum is 23.
Adding to 132402004400003 its reverse (300004400204231), we get a palindrome (432406404604234).
The spelling of 132402004400003 in words is "one hundred thirty-two trillion, four hundred two billion, four million, four hundred thousand, three".
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