13240444140211 has 4 divisors (see below), whose sum is σ = 13816115624592. Its totient is φ = 12664772655832.

The previous prime is 13240444140191. The next prime is 13240444140221. The reversal of 13240444140211 is 11204144404231.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 13240444140211 - 2¹⁹ = 13240443615923 is a prime.

It is a super-2 number, since 2×13240444140211² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13240444140221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 287835742156 + ... + 287835742201.

It is an arithmetic number, because the mean of its divisors is an integer number (3454028906148).

Almost surely, 2^{13240444140211} is an apocalyptic number.

13240444140211 is a deficient number, since it is larger than the sum of its proper divisors (575671484381).

13240444140211 is an equidigital number, since it uses as much as digits as its factorization.

13240444140211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 575671484380.

The product of its (nonzero) digits is 12288, while the sum is 31.

Adding to 13240444140211 its reverse (11204144404231), we get a palindrome (24444588544442).

The spelling of 13240444140211 in words is "thirteen trillion, two hundred forty billion, four hundred forty-four million, one hundred forty thousand, two hundred eleven".