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132405024000041 = 1349985723816599
BaseRepresentation
bin11110000110101111110010…
…011011000000100000101001
3122100210210111202222011011022
4132012233302123000200221
5114323310442121000131
61145334010040542225
736613642632334142
oct3606576233004051
9570723452864138
10132405024000041
113920872328aa61
1212a24b92781975
1358b598126a480
14249a61a15cac9
15104925a06737b
hex786bf26c0829

132405024000041 has 16 divisors (see below), whose sum is σ = 143042499600000. Its totient is φ = 121832759138688.

The previous prime is 132405023999971. The next prime is 132405024000071. The reversal of 132405024000041 is 140000420504231.

It is a de Polignac number, because none of the positive numbers 2k-132405024000041 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (132405024000071) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6348941 + ... + 17467658.

It is an arithmetic number, because the mean of its divisors is an integer number (8940156225000).

Almost surely, 2132405024000041 is an apocalyptic number.

It is an amenable number.

132405024000041 is a deficient number, since it is larger than the sum of its proper divisors (10637475599959).

132405024000041 is a wasteful number, since it uses less digits than its factorization.

132405024000041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23817968.

The product of its (nonzero) digits is 3840, while the sum is 26.

Adding to 132405024000041 its reverse (140000420504231), we get a palindrome (272405444504272).

The spelling of 132405024000041 in words is "one hundred thirty-two trillion, four hundred five billion, twenty-four million, forty-one", and thus it is an aban number.

Divisors: 1 13 499 857 6487 11141 427643 5559359 23816599 309615787 11884482901 20410825343 154498277713 265340729459 10185001846157 132405024000041