Base | Representation |
---|---|
bin | 11000101010011001… |
… | …00110001011110011 |
3 | 1021011202101101111101 |
4 | 30111030212023303 |
5 | 204104033304210 |
6 | 10025502225231 |
7 | 646053416215 |
oct | 142514461363 |
9 | 37152341441 |
10 | 13240525555 |
11 | 5684a27904 |
12 | 2696285217 |
13 | 1330177b0a |
14 | 8d869a5b5 |
15 | 527613a3a |
hex | 3153262f3 |
13240525555 has 4 divisors (see below), whose sum is σ = 15888630672. Its totient is φ = 10592420440.
The previous prime is 13240525553. The next prime is 13240525559. The reversal of 13240525555 is 55552504231.
13240525555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 13240525555 - 21 = 13240525553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13240525553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1324052551 + ... + 1324052560.
It is an arithmetic number, because the mean of its divisors is an integer number (3972157668).
Almost surely, 213240525555 is an apocalyptic number.
13240525555 is a deficient number, since it is larger than the sum of its proper divisors (2648105117).
13240525555 is an equidigital number, since it uses as much as digits as its factorization.
13240525555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2648105116.
The product of its (nonzero) digits is 150000, while the sum is 37.
The spelling of 13240525555 in words is "thirteen billion, two hundred forty million, five hundred twenty-five thousand, five hundred fifty-five".
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