Base | Representation |
---|---|
bin | 11110000110110100011101… |
… | …011110010011110100100011 |
3 | 122100211021110102211000112201 |
4 | 132012310131132103310203 |
5 | 114323401231030100110 |
6 | 1145340155550034031 |
7 | 36614211154310221 |
oct | 3606643536236443 |
9 | 570737412730481 |
10 | 132410041253155 |
11 | 3920a868401536 |
12 | 12a25b52aa8917 |
13 | 58b62a085a0b3 |
14 | 249a974631b11 |
15 | 104945077ab3a |
hex | 786d1d793d23 |
132410041253155 has 8 divisors (see below), whose sum is σ = 158892534990000. Its totient is φ = 105927709345056.
The previous prime is 132410041253111. The next prime is 132410041253227. The reversal of 132410041253155 is 551352140014231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132410041253155 - 223 = 132410032864547 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38649780 + ... + 41935969.
It is an arithmetic number, because the mean of its divisors is an integer number (19861566873750).
Almost surely, 2132410041253155 is an apocalyptic number.
132410041253155 is a deficient number, since it is larger than the sum of its proper divisors (26482493736845).
132410041253155 is an equidigital number, since it uses as much as digits as its factorization.
132410041253155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 80914373.
The product of its (nonzero) digits is 72000, while the sum is 37.
Adding to 132410041253155 its reverse (551352140014231), we get a palindrome (683762181267386).
The spelling of 132410041253155 in words is "one hundred thirty-two trillion, four hundred ten billion, forty-one million, two hundred fifty-three thousand, one hundred fifty-five".
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