Base | Representation |
---|---|
bin | 11000101010011100… |
… | …11100011111010011 |
3 | 1021011210022000012122 |
4 | 30111032130133103 |
5 | 204104144311011 |
6 | 10025520444455 |
7 | 646060505036 |
oct | 142516343723 |
9 | 37153260178 |
10 | 13241010131 |
11 | 5685228988 |
12 | 269647972b |
13 | 13302b754b |
14 | 8d878501d |
15 | 5276ac3db |
hex | 31539c7d3 |
13241010131 has 4 divisors (see below), whose sum is σ = 13241486064. Its totient is φ = 13240534200.
The previous prime is 13241010109. The next prime is 13241010151. The reversal of 13241010131 is 13101014231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13241010131 is a prime.
It is a super-2 number, since 2×132410101312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13241010151) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193460 + ... + 252801.
It is an arithmetic number, because the mean of its divisors is an integer number (3310371516).
Almost surely, 213241010131 is an apocalyptic number.
13241010131 is a deficient number, since it is larger than the sum of its proper divisors (475933).
13241010131 is an equidigital number, since it uses as much as digits as its factorization.
13241010131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 475932.
The product of its (nonzero) digits is 72, while the sum is 17.
Adding to 13241010131 its reverse (13101014231), we get a palindrome (26342024362).
The spelling of 13241010131 in words is "thirteen billion, two hundred forty-one million, ten thousand, one hundred thirty-one".
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