13241120113 has 4 divisors (see below), whose sum is σ = 14259667828. Its totient is φ = 12222572400.

The previous prime is 13241120069. The next prime is 13241120129. The reversal of 13241120113 is 31102114231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 649587169 + 12591532944 = 25487^2 + 112212^2 .

It is a cyclic number.

It is not a de Polignac number, because 13241120113 - 2¹³ = 13241111921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13241120173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509273838 + ... + 509273863.

It is an arithmetic number, because the mean of its divisors is an integer number (3564916957).

Almost surely, 2^13241120113 is an apocalyptic number.

13241120113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13241120113 is a deficient number, since it is larger than the sum of its proper divisors (1018547715).

13241120113 is a wasteful number, since it uses less digits than its factorization.

13241120113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1018547714.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 13241120113 its reverse (31102114231), we get a palindrome (44343234344).

The spelling of 13241120113 in words is "thirteen billion, two hundred forty-one million, one hundred twenty thousand, one hundred thirteen".