1324120431555 has 16 divisors (see below), whose sum is σ = 2353991878560. Its totient is φ = 706197563424.

The previous prime is 1324120431547. The next prime is 1324120431593. The reversal of 1324120431555 is 5551340214231.

1324120431555 is a `hidden beast` number, since 1 + 3 + 2 + 41 + 20 + 43 + 1 + 555 = 666.

It is not a de Polignac number, because 1324120431555 - 2³ = 1324120431547 is a prime.

It is a super-2 number, since 2×1324120431555² (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4904149612 + ... + 4904149881.

It is an arithmetic number, because the mean of its divisors is an integer number (147124492410).

Almost surely, 2^{1324120431555} is an apocalyptic number.

1324120431555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1324120431555 is a deficient number, since it is larger than the sum of its proper divisors (1029871447005).

1324120431555 is an equidigital number, since it uses as much as digits as its factorization.

1324120431555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9808299507 (or 9808299501 counting only the distinct ones).

The product of its (nonzero) digits is 72000, while the sum is 36.

Adding to 1324120431555 its reverse (5551340214231), we get a palindrome (6875460645786).

The spelling of 1324120431555 in words is "one trillion, three hundred twenty-four billion, one hundred twenty million, four hundred thirty-one thousand, five hundred fifty-five".