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13241214001 = 49926535499
BaseRepresentation
bin11000101010011110…
…01110010000110001
31021011210200100212101
430111033032100301
5204104222322001
610025525100401
7646062314311
oct142517162061
937153610771
1013241214001
115685358074
122696557701
131330359292
148d87d9441
155276eca01
hex3153ce431

13241214001 has 4 divisors (see below), whose sum is σ = 13267750000. Its totient is φ = 13214678004.

The previous prime is 13241213983. The next prime is 13241214037. The reversal of 13241214001 is 10041214231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13241214001 - 217 = 13241082929 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13241214001.

It is not an unprimeable number, because it can be changed into a prime (13241214071) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13267251 + ... + 13268248.

It is an arithmetic number, because the mean of its divisors is an integer number (3316937500).

Almost surely, 213241214001 is an apocalyptic number.

It is an amenable number.

13241214001 is a deficient number, since it is larger than the sum of its proper divisors (26535999).

13241214001 is an equidigital number, since it uses as much as digits as its factorization.

13241214001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26535998.

The product of its (nonzero) digits is 192, while the sum is 19.

Adding to 13241214001 its reverse (10041214231), we get a palindrome (23282428232).

The spelling of 13241214001 in words is "thirteen billion, two hundred forty-one million, two hundred fourteen thousand, one".

Divisors: 1 499 26535499 13241214001