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132412442433 = 3359449273821
BaseRepresentation
bin111101101010001100…
…1011000011101000001
3110122210001101000111120
41323110121120131001
54132140041124213
6140455054102453
712365206122135
oct1732431303501
9418701330446
10132412442433
115117940a907
12217b47aaa29
13c64292896b
1465a1a473c5
15369ea46423
hex1ed4658741

132412442433 has 16 divisors (see below), whose sum is σ = 177436656000. Its totient is φ = 87832693760.

The previous prime is 132412442429. The next prime is 132412442471. The reversal of 132412442433 is 334244214231.

It is a cyclic number.

It is not a de Polignac number, because 132412442433 - 22 = 132412442429 is a prime.

It is a super-2 number, since 2×1324124424332 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 132412442394 and 132412442403.

It is not an unprimeable number, because it can be changed into a prime (132412442413) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 346663 + ... + 620483.

It is an arithmetic number, because the mean of its divisors is an integer number (11089791000).

Almost surely, 2132412442433 is an apocalyptic number.

It is an amenable number.

132412442433 is a deficient number, since it is larger than the sum of its proper divisors (45024213567).

132412442433 is a wasteful number, since it uses less digits than its factorization.

132412442433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 274632.

The product of its digits is 55296, while the sum is 33.

Adding to 132412442433 its reverse (334244214231), we get a palindrome (466656656664).

The spelling of 132412442433 in words is "one hundred thirty-two billion, four hundred twelve million, four hundred forty-two thousand, four hundred thirty-three".

Divisors: 1 3 359 449 1077 1347 161191 273821 483573 821463 98301739 122945629 294905217 368836887 44137480811 132412442433