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13241353000555 = 519335938221753
BaseRepresentation
bin1100000010101111111000…
…1001000101011001101011
31201212212020122202022010001
43000223332021011121223
53213421242332004210
644054554341003431
72534441033302261
oct300537611053153
951785218668101
1013241353000555
114245698627309
12159a31a3b3577
13750867460b94
1433ac56270431
1517e6882a203a
hexc0afe24566b

13241353000555 has 16 divisors (see below), whose sum is σ = 16016443796160. Its totient is φ = 10508841381888.

The previous prime is 13241353000549. The next prime is 13241353000597. The reversal of 13241353000555 is 55500035314231.

13241353000555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a cyclic number.

It is not a de Polignac number, because 13241353000555 - 235 = 13206993262187 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 18764442 + ... + 19457311.

It is an arithmetic number, because the mean of its divisors is an integer number (1001027737260).

Almost surely, 213241353000555 is an apocalyptic number.

13241353000555 is a deficient number, since it is larger than the sum of its proper divisors (2775090795605).

13241353000555 is a wasteful number, since it uses less digits than its factorization.

13241353000555 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38222310.

The product of its (nonzero) digits is 135000, while the sum is 37.

Adding to 13241353000555 its reverse (55500035314231), we get a palindrome (68741388314786).

The spelling of 13241353000555 in words is "thirteen trillion, two hundred forty-one billion, three hundred fifty-three million, five hundred fifty-five", and thus it is an aban number.

Divisors: 1 5 193 359 965 1795 69287 346435 38221753 191108765 7376798329 13721609327 36883991645 68608046635 2648270600111 13241353000555