Base | Representation |
---|---|
bin | 11110000110110111101101… |
… | …101010111011000001000011 |
3 | 122100211121110212110010202021 |
4 | 132012313231222323001003 |
5 | 114323430404230022410 |
6 | 1145341534324302311 |
7 | 36614363550116113 |
oct | 3606675552730103 |
9 | 570747425403667 |
10 | 132413534220355 |
11 | 392112a0065493 |
12 | 12a26768841997 |
13 | 58b67094035ab |
14 | 249abc64bd043 |
15 | 10495a7248eda |
hex | 786dedabb043 |
132413534220355 has 8 divisors (see below), whose sum is σ = 158896302840864. Its totient is φ = 105930786192000.
The previous prime is 132413534220337. The next prime is 132413534220397. The reversal of 132413534220355 is 553022435314231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132413534220355 - 29 = 132413534219843 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22396795 + ... + 27684715.
It is an arithmetic number, because the mean of its divisors is an integer number (19862037855108).
Almost surely, 2132413534220355 is an apocalyptic number.
132413534220355 is a deficient number, since it is larger than the sum of its proper divisors (26482768620509).
132413534220355 is an equidigital number, since it uses as much as digits as its factorization.
132413534220355 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10296077.
The product of its (nonzero) digits is 1296000, while the sum is 43.
Adding to 132413534220355 its reverse (553022435314231), we get a palindrome (685435969534586).
The spelling of 132413534220355 in words is "one hundred thirty-two trillion, four hundred thirteen billion, five hundred thirty-four million, two hundred twenty thousand, three hundred fifty-five".
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