Base | Representation |
---|---|
bin | 111101101010100000… |
… | …1101010000000110001 |
3 | 110122210210020101220202 |
4 | 1323111001222000301 |
5 | 4132200242000423 |
6 | 140500112244545 |
7 | 12365364633425 |
oct | 1732501520061 |
9 | 418723211822 |
10 | 132423000113 |
11 | 51184370a68 |
12 | 217b8240755 |
13 | c644b84301 |
14 | 65a31d4b85 |
15 | 36a092e728 |
hex | 1ed506a031 |
132423000113 has 4 divisors (see below), whose sum is σ = 133734119028. Its totient is φ = 131111881200.
The previous prime is 132423000109. The next prime is 132423000137. The reversal of 132423000113 is 311000324231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 90966782449 + 41456217664 = 301607^2 + 203608^2 .
It is a cyclic number.
It is not a de Polignac number, because 132423000113 - 22 = 132423000109 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132423000103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 655559306 + ... + 655559507.
It is an arithmetic number, because the mean of its divisors is an integer number (33433529757).
Almost surely, 2132423000113 is an apocalyptic number.
It is an amenable number.
132423000113 is a deficient number, since it is larger than the sum of its proper divisors (1311118915).
132423000113 is a wasteful number, since it uses less digits than its factorization.
132423000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1311118914.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 132423000113 its reverse (311000324231), we get a palindrome (443423324344).
The spelling of 132423000113 in words is "one hundred thirty-two billion, four hundred twenty-three million, one hundred thirteen", and thus it is an aban number.
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