Base | Representation |
---|---|
bin | 11110000111000111011101… |
… | …011011001100001100000001 |
3 | 122100220020010011112110112222 |
4 | 132013013131123030030001 |
5 | 114324220021012430423 |
6 | 1145353412134500425 |
7 | 36615532536641306 |
oct | 3607073533141401 |
9 | 570806104473488 |
10 | 132430441530113 |
11 | 39218486875561 |
12 | 12a29aa6b04715 |
13 | 58b81a21423ac |
14 | 249b94bb510ad |
15 | 1049c467123c8 |
hex | 7871dd6cc301 |
132430441530113 has 16 divisors (see below), whose sum is σ = 140723619624000. Its totient is φ = 124270992437760.
The previous prime is 132430441530071. The next prime is 132430441530119. The reversal of 132430441530113 is 311035144034231.
It is a cyclic number.
It is not a de Polignac number, because 132430441530113 - 216 = 132430441464577 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132430441530119) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16258388 + ... + 23004261.
It is an arithmetic number, because the mean of its divisors is an integer number (8795226226500).
Almost surely, 2132430441530113 is an apocalyptic number.
It is an amenable number.
132430441530113 is a deficient number, since it is larger than the sum of its proper divisors (8293178093887).
132430441530113 is a wasteful number, since it uses less digits than its factorization.
132430441530113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 39264352.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 132430441530113 its reverse (311035144034231), we get a palindrome (443465585564344).
The spelling of 132430441530113 in words is "one hundred thirty-two trillion, four hundred thirty billion, four hundred forty-one million, five hundred thirty thousand, one hundred thirteen".
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