1324333140403 has 12 divisors (see below), whose sum is σ = 1659054704160. Its totient is φ = 1047824022672.

The previous prime is 1324333140331. The next prime is 1324333140413. The reversal of 1324333140403 is 3040413334231.

It is a de Polignac number, because none of the positive numbers 2^k-1324333140403 is a prime.

It is a super-2 number, since 2×1324333140403² (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1324333140413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 1039507323 + ... + 1039508596.

It is an arithmetic number, because the mean of its divisors is an integer number (138254558680).

Almost surely, 2^{1324333140403} is an apocalyptic number.

1324333140403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1324333140403 is a deficient number, since it is larger than the sum of its proper divisors (334721563757).

1324333140403 is a wasteful number, since it uses less digits than its factorization.

1324333140403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2079015946 (or 2079015939 counting only the distinct ones).

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 1324333140403 its reverse (3040413334231), we get a palindrome (4364746474634).

The spelling of 1324333140403 in words is "one trillion, three hundred twenty-four billion, three hundred thirty-three million, one hundred forty thousand, four hundred three".