Base | Representation |
---|---|
bin | 11110000111010100011101… |
… | …100011011001011001110001 |
3 | 122100221120011010020022222011 |
4 | 132013110131203121121301 |
5 | 114324432113443400410 |
6 | 1145404041331042521 |
7 | 36616535520512443 |
oct | 3607243543313161 |
9 | 570846133208864 |
10 | 132444402325105 |
11 | 392233a0326462 |
12 | 12a30742440441 |
13 | 58b95b85a5530 |
14 | 249c4b3d40493 |
15 | 104a2b219e18a |
hex | 78751d8d9671 |
132444402325105 has 16 divisors (see below), whose sum is σ = 173569608946944. Its totient is φ = 96427560519360.
The previous prime is 132444402324929. The next prime is 132444402325111. The reversal of 132444402325105 is 501523204444231.
It is not a de Polignac number, because 132444402325105 - 29 = 132444402324593 is a prime.
It is a super-2 number, since 2×1324444023251052 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14349334749 + ... + 14349343978.
It is an arithmetic number, because the mean of its divisors is an integer number (10848100559184).
Almost surely, 2132444402325105 is an apocalyptic number.
It is an amenable number.
132444402325105 is a deficient number, since it is larger than the sum of its proper divisors (41125206621839).
132444402325105 is a wasteful number, since it uses less digits than its factorization.
132444402325105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28698678816.
The product of its (nonzero) digits is 460800, while the sum is 40.
Adding to 132444402325105 its reverse (501523204444231), we get a palindrome (633967606769336).
The spelling of 132444402325105 in words is "one hundred thirty-two trillion, four hundred forty-four billion, four hundred two million, three hundred twenty-five thousand, one hundred five".
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