Base | Representation |
---|---|
bin | 1100000011001101100101… |
… | …0100000001000010111011 |
3 | 1201220121211020120001200122 |
4 | 3000303121110001002323 |
5 | 3214034104202401044 |
6 | 44102353401323455 |
7 | 2535142424454200 |
oct | 300633124010273 |
9 | 51817736501618 |
10 | 13249325043899 |
11 | 424900963a48a |
12 | 159b98419658b |
13 | 751537c660a9 |
14 | 33b3b0d3bca7 |
15 | 17e9a30c8dee |
hex | c0cd95010bb |
13249325043899 has 6 divisors (see below), whose sum is σ = 15412480153164. Its totient is φ = 11356564323300.
The previous prime is 13249325043853. The next prime is 13249325043917. The reversal of 13249325043899 is 99834052394231.
It is not a de Polignac number, because 13249325043899 - 212 = 13249325039803 is a prime.
It is a super-2 number, since 2×132493250438992 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13249325003899) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 135197194277 + ... + 135197194374.
It is an arithmetic number, because the mean of its divisors is an integer number (2568746692194).
Almost surely, 213249325043899 is an apocalyptic number.
13249325043899 is a deficient number, since it is larger than the sum of its proper divisors (2163155109265).
13249325043899 is an equidigital number, since it uses as much as digits as its factorization.
13249325043899 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 270394388665 (or 270394388658 counting only the distinct ones).
The product of its (nonzero) digits is 50388480, while the sum is 62.
The spelling of 13249325043899 in words is "thirteen trillion, two hundred forty-nine billion, three hundred twenty-five million, forty-three thousand, eight hundred ninety-nine".
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