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132500100520345 = 590884929157781
BaseRepresentation
bin11110001000001000010101…
…011011001001100110011001
3122101010212220211012210222011
4132020020111123021212121
5114331340201213122340
61145445412244425521
736623550003406345
oct3610102533114631
9571125824183864
10132500100520345
1139244a82522978
1212a3b4a76a82a1
1358c1923a308cc
1424a107935a625
15104b971e130ea
hex7882156c9999

132500100520345 has 8 divisors (see below), whose sum is σ = 159000301024200. Its totient is φ = 105999960149760.

The previous prime is 132500100520327. The next prime is 132500100520393. The reversal of 132500100520345 is 543025001005231.

It can be written as a sum of positive squares in 4 ways, for example, as 68805830525184 + 63694269995161 = 8294928^2 + 7980869^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132500100520345 - 25 = 132500100520313 is a prime.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10034646 + ... + 19123135.

It is an arithmetic number, because the mean of its divisors is an integer number (19875037628025).

Almost surely, 2132500100520345 is an apocalyptic number.

It is an amenable number.

132500100520345 is a deficient number, since it is larger than the sum of its proper divisors (26500200503855).

132500100520345 is an equidigital number, since it uses as much as digits as its factorization.

132500100520345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30066635.

The product of its (nonzero) digits is 18000, while the sum is 31.

Adding to 132500100520345 its reverse (543025001005231), we get a palindrome (675525101525576).

The spelling of 132500100520345 in words is "one hundred thirty-two trillion, five hundred billion, one hundred million, five hundred twenty thousand, three hundred forty-five".

Divisors: 1 5 908849 4544245 29157781 145788905 26500020104069 132500100520345