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1325001035 = 5793354433
BaseRepresentation
bin100111011111001…
…1110100101001011
310102100020000201102
41032332132211023
510203200013120
6335251212015
744556215531
oct11676364513
93370200642
101325001035
1161aa23986
1230b8a700b
1318167c7a7
14c7d8c151
157b4ccd75
hex4ef9e94b

1325001035 has 8 divisors (see below), whose sum is σ = 1610128320. Its totient is φ = 1046582784.

The previous prime is 1325001031. The next prime is 1325001037. The reversal of 1325001035 is 5301005231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1325001035 - 22 = 1325001031 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1325000998 and 1325001016.

It is not an unprimeable number, because it can be changed into a prime (1325001031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1676822 + ... + 1677611.

It is an arithmetic number, because the mean of its divisors is an integer number (201266040).

Almost surely, 21325001035 is an apocalyptic number.

1325001035 is a deficient number, since it is larger than the sum of its proper divisors (285127285).

1325001035 is an equidigital number, since it uses as much as digits as its factorization.

1325001035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3354517.

The product of its (nonzero) digits is 450, while the sum is 20.

The square root of 1325001035 is about 36400.5636632182. The cubic root of 1325001035 is about 1098.3449034979.

Adding to 1325001035 its reverse (5301005231), we get a palindrome (6626006266).

The spelling of 1325001035 in words is "one billion, three hundred twenty-five million, one thousand, thirty-five".

Divisors: 1 5 79 395 3354433 16772165 265000207 1325001035