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132500435344041 = 3208321203462209
BaseRepresentation
bin11110001000001000101001…
…011000011001101010101001
3122101010220210011020121201210
4132020020221120121222221
5114331341342422002131
61145445505405103333
736623561210354622
oct3610105130315251
9571126704217653
10132500435344041
1139245134521976
1212a3b57b857b49
1358c197820213b
1424a10ab9d6a49
15104b991500146
hex788229619aa9

132500435344041 has 8 divisors (see below), whose sum is σ = 176752060982560. Its totient is φ = 88291216634112.

The previous prime is 132500435343989. The next prime is 132500435344073. The reversal of 132500435344041 is 140443534005231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132500435344041 - 226 = 132500368235177 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132500435344141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10601724856 + ... + 10601737353.

It is an arithmetic number, because the mean of its divisors is an integer number (22094007622820).

Almost surely, 2132500435344041 is an apocalyptic number.

It is an amenable number.

132500435344041 is a deficient number, since it is larger than the sum of its proper divisors (44251625638519).

132500435344041 is a wasteful number, since it uses less digits than its factorization.

132500435344041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21203464295.

The product of its (nonzero) digits is 345600, while the sum is 39.

Adding to 132500435344041 its reverse (140443534005231), we get a palindrome (272943969349272).

The spelling of 132500435344041 in words is "one hundred thirty-two trillion, five hundred billion, four hundred thirty-five million, three hundred forty-four thousand, forty-one".

Divisors: 1 3 2083 6249 21203462209 63610386627 44166811781347 132500435344041