Base | Representation |
---|---|
bin | 1100000011010000010011… |
… | …1110001000110000101011 |
3 | 1201220200201021210222120111 |
4 | 3000310010332020300223 |
5 | 3214042104210141320 |
6 | 44102554204435151 |
7 | 2535166530336553 |
oct | 300640476106053 |
9 | 51820637728514 |
10 | 13250057505835 |
11 | 4249355040a27 |
12 | 159bb49548ab7 |
13 | 75162392cc17 |
14 | 33b440326163 |
15 | 17e9e755ea5a |
hex | c0d04f88c2b |
13250057505835 has 4 divisors (see below), whose sum is σ = 15900069007008. Its totient is φ = 10600046004664.
The previous prime is 13250057505791. The next prime is 13250057505887. The reversal of 13250057505835 is 53850575005231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13250057505835 - 233 = 13241467571243 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1325005750579 + ... + 1325005750588.
It is an arithmetic number, because the mean of its divisors is an integer number (3975017251752).
Almost surely, 213250057505835 is an apocalyptic number.
13250057505835 is a deficient number, since it is larger than the sum of its proper divisors (2650011501173).
13250057505835 is an equidigital number, since it uses as much as digits as its factorization.
13250057505835 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2650011501172.
The product of its (nonzero) digits is 3150000, while the sum is 49.
The spelling of 13250057505835 in words is "thirteen trillion, two hundred fifty billion, fifty-seven million, five hundred five thousand, eight hundred thirty-five".
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