Base | Representation |
---|---|
bin | 11000101011100101… |
… | …01010011011111011 |
3 | 1021012110011100221211 |
4 | 30111302222123323 |
5 | 204114112120233 |
6 | 10030500143551 |
7 | 646234300201 |
oct | 142562523373 |
9 | 37173140854 |
10 | 13250504443 |
11 | 568a623120 |
12 | 2699697bb7 |
13 | 133225cb97 |
14 | 8d9b37071 |
15 | 5284355cd |
hex | 315caa6fb |
13250504443 has 4 divisors (see below), whose sum is σ = 14455095768. Its totient is φ = 12045913120.
The previous prime is 13250504419. The next prime is 13250504461. The reversal of 13250504443 is 34440505231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34440505231 = 11 ⋅3130955021.
It is a cyclic number.
It is not a de Polignac number, because 13250504443 - 213 = 13250496251 is a prime.
It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13250504473) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 602295646 + ... + 602295667.
It is an arithmetic number, because the mean of its divisors is an integer number (3613773942).
Almost surely, 213250504443 is an apocalyptic number.
13250504443 is a deficient number, since it is larger than the sum of its proper divisors (1204591325).
13250504443 is a wasteful number, since it uses less digits than its factorization.
13250504443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1204591324.
The product of its (nonzero) digits is 28800, while the sum is 31.
The spelling of 13250504443 in words is "thirteen billion, two hundred fifty million, five hundred four thousand, four hundred forty-three".
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