Base | Representation |
---|---|
bin | 1100000011010010000111… |
… | …1110011011100011111001 |
3 | 1201220201222012110122121022 |
4 | 3000310201332123203321 |
5 | 3214044103243401410 |
6 | 44103114350352225 |
7 | 2535214556452103 |
oct | 300644176334371 |
9 | 51821865418538 |
10 | 13250544122105 |
11 | 4249584796a34 |
12 | 15a00644bb675 |
13 | 7516a06aa244 |
14 | 33b488bd6573 |
15 | 17ea25132455 |
hex | c0d21f9b8f9 |
13250544122105 has 16 divisors (see below), whose sum is σ = 16192216042560. Its totient is φ = 10406550134208.
The previous prime is 13250544122047. The next prime is 13250544122131. The reversal of 13250544122105 is 50122144505231.
It is a cyclic number.
It is not a de Polignac number, because 13250544122105 - 28 = 13250544121849 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30422987 + ... + 30855456.
It is an arithmetic number, because the mean of its divisors is an integer number (1012013502660).
Almost surely, 213250544122105 is an apocalyptic number.
It is an amenable number.
13250544122105 is a deficient number, since it is larger than the sum of its proper divisors (2941671920455).
13250544122105 is an equidigital number, since it uses as much as digits as its factorization.
13250544122105 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 61279240.
The product of its (nonzero) digits is 48000, while the sum is 35.
Adding to 13250544122105 its reverse (50122144505231), we get a palindrome (63372688627336).
The spelling of 13250544122105 in words is "thirteen trillion, two hundred fifty billion, five hundred forty-four million, one hundred twenty-two thousand, one hundred five".
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