Base | Representation |
---|---|
bin | 10011010010001100011… |
… | …001001110111011000011 |
3 | 11200200120211200000012120 |
4 | 103102030121032323003 |
5 | 133203010032232011 |
6 | 2452442501455323 |
7 | 164512552431123 |
oct | 23221431167303 |
9 | 4620524600176 |
10 | 1325205352131 |
11 | 47101a967321 |
12 | 194a00711543 |
13 | 97c7404009b |
14 | 481d6d08c83 |
15 | 24711b5ca06 |
hex | 1348c64eec3 |
1325205352131 has 4 divisors (see below), whose sum is σ = 1766940469512. Its totient is φ = 883470234752.
The previous prime is 1325205352099. The next prime is 1325205352139. The reversal of 1325205352131 is 1312535025231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1325205352131 - 25 = 1325205352099 is a prime.
It is a super-2 number, since 2×13252053521312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1325205352092 and 1325205352101.
It is not an unprimeable number, because it can be changed into a prime (1325205352139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220867558686 + ... + 220867558691.
It is an arithmetic number, because the mean of its divisors is an integer number (441735117378).
Almost surely, 21325205352131 is an apocalyptic number.
1325205352131 is a deficient number, since it is larger than the sum of its proper divisors (441735117381).
1325205352131 is an equidigital number, since it uses as much as digits as its factorization.
1325205352131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 441735117380.
The product of its (nonzero) digits is 27000, while the sum is 33.
The spelling of 1325205352131 in words is "one trillion, three hundred twenty-five billion, two hundred five million, three hundred fifty-two thousand, one hundred thirty-one".
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