Base | Representation |
---|---|
bin | 111101101101011100… |
… | …0110011010001010011 |
3 | 110200001122021200200011 |
4 | 1323122320303101103 |
5 | 4132400430421120 |
6 | 140513544135351 |
7 | 12401000551525 |
oct | 1733270632123 |
9 | 420048250604 |
10 | 132521342035 |
11 | 5122492a785 |
12 | 21825167557 |
13 | c65c3671b4 |
14 | 65b22b3a15 |
15 | 36a93a7c5a |
hex | 1edae33453 |
132521342035 has 4 divisors (see below), whose sum is σ = 159025610448. Its totient is φ = 106017073624.
The previous prime is 132521342033. The next prime is 132521342053. The reversal of 132521342035 is 530243125231.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530243125231 = 409 ⋅1296437959.
It is a cyclic number.
It is not a de Polignac number, because 132521342035 - 21 = 132521342033 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 132521341988 and 132521342006.
It is not an unprimeable number, because it can be changed into a prime (132521342033) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13252134199 + ... + 13252134208.
It is an arithmetic number, because the mean of its divisors is an integer number (39756402612).
Almost surely, 2132521342035 is an apocalyptic number.
132521342035 is a deficient number, since it is larger than the sum of its proper divisors (26504268413).
132521342035 is an equidigital number, since it uses as much as digits as its factorization.
132521342035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26504268412.
The product of its (nonzero) digits is 21600, while the sum is 31.
Adding to 132521342035 its reverse (530243125231), we get a palindrome (662764467266).
The spelling of 132521342035 in words is "one hundred thirty-two billion, five hundred twenty-one million, three hundred forty-two thousand, thirty-five".
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