132526014331 has 4 divisors (see below), whose sum is σ = 133698811032. Its totient is φ = 131353217632.

The previous prime is 132526014323. The next prime is 132526014373. The reversal of 132526014331 is 133410625231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132526014331 - 2³ = 132526014323 is a prime.

It is a super-2 number, since 2×132526014331² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132526014293 and 132526014302.

It is not an unprimeable number, because it can be changed into a prime (132526014931) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 586398181 + ... + 586398406.

It is an arithmetic number, because the mean of its divisors is an integer number (33424702758).

Almost surely, 2^132526014331 is an apocalyptic number.

132526014331 is a deficient number, since it is larger than the sum of its proper divisors (1172796701).

132526014331 is a wasteful number, since it uses less digits than its factorization.

132526014331 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1172796700.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 132526014331 its reverse (133410625231), we get a palindrome (265936639562).

The spelling of 132526014331 in words is "one hundred thirty-two billion, five hundred twenty-six million, fourteen thousand, three hundred thirty-one".