Base | Representation |
---|---|
bin | 10011010010010101010… |
… | …000010010011100111011 |
3 | 11200200222012101012210222 |
4 | 103102111100102130323 |
5 | 133203311111032420 |
6 | 2452505331530255 |
7 | 164516336066264 |
oct | 23222520223473 |
9 | 4620865335728 |
10 | 1325354002235 |
11 | 47109686734a |
12 | 194a4245998b |
13 | 97c98a88723 |
14 | 4820c96196b |
15 | 2471ec22225 |
hex | 1349541273b |
1325354002235 has 4 divisors (see below), whose sum is σ = 1590424802688. Its totient is φ = 1060283201784.
The previous prime is 1325354002229. The next prime is 1325354002277. The reversal of 1325354002235 is 5322004535231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1325354002235 - 210 = 1325354001211 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1325354002195 and 1325354002204.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132535400219 + ... + 132535400228.
It is an arithmetic number, because the mean of its divisors is an integer number (397606200672).
Almost surely, 21325354002235 is an apocalyptic number.
1325354002235 is a deficient number, since it is larger than the sum of its proper divisors (265070800453).
1325354002235 is an equidigital number, since it uses as much as digits as its factorization.
1325354002235 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 265070800452.
The product of its (nonzero) digits is 108000, while the sum is 35.
Adding to 1325354002235 its reverse (5322004535231), we get a palindrome (6647358537466).
The spelling of 1325354002235 in words is "one trillion, three hundred twenty-five billion, three hundred fifty-four million, two thousand, two hundred thirty-five".
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