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132540051355441 = 416748249017603
BaseRepresentation
bin11110001000101101100010…
…101011011111011100110001
3122101021201001001202111220021
4132020231202223133130301
5114333014011121333231
61145520020425443441
736626463013041262
oct3610554253373461
9571251031674807
10132540051355441
113925aa13750664
1212a47197040581
1358c561c85abc2
1424a2d891aa969
15104ca0e437811
hex788b62adf731

132540051355441 has 8 divisors (see below), whose sum is σ = 137799194277024. Its totient is φ = 127377406469280.

The previous prime is 132540051355429. The next prime is 132540051355519. The reversal of 132540051355441 is 144553150045231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132540051355441 - 211 = 132540051353393 is a prime.

It is a super-2 number, since 2×1325400513554412 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132540052355441) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24124506055 + ... + 24124511548.

It is an arithmetic number, because the mean of its divisors is an integer number (17224899284628).

Almost surely, 2132540051355441 is an apocalyptic number.

It is an amenable number.

132540051355441 is a deficient number, since it is larger than the sum of its proper divisors (5259142921583).

132540051355441 is an equidigital number, since it uses as much as digits as its factorization.

132540051355441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48249017711.

The product of its (nonzero) digits is 720000, while the sum is 43.

The spelling of 132540051355441 in words is "one hundred thirty-two trillion, five hundred forty billion, fifty-one million, three hundred fifty-five thousand, four hundred forty-one".

Divisors: 1 41 67 2747 48249017603 1978209721723 3232684179401 132540051355441