Base | Representation |
---|---|
bin | 1100000011011111111100… |
… | …0000000010111000011001 |
3 | 1201221002112122002010011020 |
4 | 3000313333000002320121 |
5 | 3214124202042410131 |
6 | 44104530333553053 |
7 | 2535405504520461 |
oct | 300677700027031 |
9 | 51832478063136 |
10 | 13254252310041 |
11 | 4250107989466 |
12 | 15a091a345789 |
13 | 751b41a099a2 |
14 | 33b71b4a8ba1 |
15 | 17eb90964996 |
hex | c0dff002e19 |
13254252310041 has 16 divisors (see below), whose sum is σ = 18489355100160. Its totient is φ = 8429686206480.
The previous prime is 13254252310027. The next prime is 13254252310043. The reversal of 13254252310041 is 14001325245231.
It is not a de Polignac number, because 13254252310041 - 226 = 13254185201177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13254252309984 and 13254252310011.
It is not an unprimeable number, because it can be changed into a prime (13254252310043) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 253391545 + ... + 253443846.
It is an arithmetic number, because the mean of its divisors is an integer number (1155584693760).
Almost surely, 213254252310041 is an apocalyptic number.
It is an amenable number.
13254252310041 is a deficient number, since it is larger than the sum of its proper divisors (5235102790119).
13254252310041 is a wasteful number, since it uses less digits than its factorization.
13254252310041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 506835796.
The product of its (nonzero) digits is 28800, while the sum is 33.
Adding to 13254252310041 its reverse (14001325245231), we get a palindrome (27255577555272).
The spelling of 13254252310041 in words is "thirteen trillion, two hundred fifty-four billion, two hundred fifty-two million, three hundred ten thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.093 sec. • engine limits •