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13254341257 = 88315010579
BaseRepresentation
bin11000101100000010…
…10011001010001001
31021012201101022002001
430112001103022021
5204121102410012
610031114311001
7646312020223
oct142601231211
937181338061
1013254341257
115691803843
12269aa28461
131332ca43a1
148da455413
15528942357
hex316053289

13254341257 has 4 divisors (see below), whose sum is σ = 13269352720. Its totient is φ = 13239329796.

The previous prime is 13254341179. The next prime is 13254341333. The reversal of 13254341257 is 75214345231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13254341257 - 215 = 13254308489 is a prime.

It is the 115128-th Hogben number.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13254341957) by changing a digit.

It is a nontrivial repunit in base 115127.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7504407 + ... + 7506172.

It is an arithmetic number, because the mean of its divisors is an integer number (3317338180).

Almost surely, 213254341257 is an apocalyptic number.

It is an amenable number.

13254341257 is a deficient number, since it is larger than the sum of its proper divisors (15011463).

13254341257 is an equidigital number, since it uses as much as digits as its factorization.

13254341257 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15011462.

The product of its digits is 100800, while the sum is 37.

Adding to 13254341257 its reverse (75214345231), we get a palindrome (88468686488).

The spelling of 13254341257 in words is "thirteen billion, two hundred fifty-four million, three hundred forty-one thousand, two hundred fifty-seven".

Divisors: 1 883 15010579 13254341257