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1325434244441 = 2714890901271
BaseRepresentation
bin10011010010011010000…
…010011000110101011001
311200201011210100221102112
4103102122002120311121
5133203442131310231
62452521315442105
7164521332121466
oct23223202306531
94621153327375
101325434244441
1147112809351a
12194a652b6335
1397cac5a2118
144821948c66d
1524726cc292b
hex1349a098d59

1325434244441 has 4 divisors (see below), whose sum is σ = 1330325145984. Its totient is φ = 1320543342900.

The previous prime is 1325434244419. The next prime is 1325434244443. The reversal of 1325434244441 is 1444424345231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1325434244441 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1325434244443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2445450365 + ... + 2445450906.

It is an arithmetic number, because the mean of its divisors is an integer number (332581286496).

Almost surely, 21325434244441 is an apocalyptic number.

It is an amenable number.

1325434244441 is a deficient number, since it is larger than the sum of its proper divisors (4890901543).

1325434244441 is an equidigital number, since it uses as much as digits as its factorization.

1325434244441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4890901542.

The product of its digits is 737280, while the sum is 41.

Adding to 1325434244441 its reverse (1444424345231), we get a palindrome (2769858589672).

The spelling of 1325434244441 in words is "one trillion, three hundred twenty-five billion, four hundred thirty-four million, two hundred forty-four thousand, four hundred forty-one".

Divisors: 1 271 4890901271 1325434244441