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13254501030403 = 57123212786393
BaseRepresentation
bin1100000011100000110111…
…0100110101101000000011
31201221010011222002102100111
43000320031310311220003
53214130204230433103
644105011140532151
72535414614562643
oct300701564655003
951833158072314
1013254501030403
114250225318786
1215a09896b1057
13751b813c1ab9
1433b742530523
1517eba76e486d
hexc0e0dd35a03

13254501030403 has 4 divisors (see below), whose sum is σ = 13277713817368. Its totient is φ = 13231288243440.

The previous prime is 13254501030389. The next prime is 13254501030437. The reversal of 13254501030403 is 30403010545231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13254501030403 - 25 = 13254501030371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13254501030103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11606392626 + ... + 11606393767.

It is an arithmetic number, because the mean of its divisors is an integer number (3319428454342).

Almost surely, 213254501030403 is an apocalyptic number.

13254501030403 is a deficient number, since it is larger than the sum of its proper divisors (23212786965).

13254501030403 is an equidigital number, since it uses as much as digits as its factorization.

13254501030403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23212786964.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 13254501030403 its reverse (30403010545231), we get a palindrome (43657511575634).

The spelling of 13254501030403 in words is "thirteen trillion, two hundred fifty-four billion, five hundred one million, thirty thousand, four hundred three".

Divisors: 1 571 23212786393 13254501030403