132555404300531 has 4 divisors (see below), whose sum is σ = 132663260611200. Its totient is φ = 132447547989864.

The previous prime is 132555404300513. The next prime is 132555404300551. The reversal of 132555404300531 is 135003404555231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132555404300531 is a prime.

It is a super-2 number, since 2×132555404300531² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132555404300551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53928153491 + ... + 53928155948.

It is an arithmetic number, because the mean of its divisors is an integer number (33165815152800).

Almost surely, 2^{132555404300531} is an apocalyptic number.

132555404300531 is a deficient number, since it is larger than the sum of its proper divisors (107856310669).

132555404300531 is a wasteful number, since it uses less digits than its factorization.

132555404300531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 107856310668.

The product of its (nonzero) digits is 540000, while the sum is 41.

Adding to 132555404300531 its reverse (135003404555231), we get a palindrome (267558808855762).

The spelling of 132555404300531 in words is "one hundred thirty-two trillion, five hundred fifty-five billion, four hundred four million, three hundred thousand, five hundred thirty-one".