1326040113 has 4 divisors (see below), whose sum is σ = 1768053488. Its totient is φ = 884026740.

The previous prime is 1326039997. The next prime is 1326040139. The reversal of 1326040113 is 3110406231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1326040113 - 2⁸ = 1326039857 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1326040113.

It is not an unprimeable number, because it can be changed into a prime (1326040213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 221006683 + ... + 221006688.

It is an arithmetic number, because the mean of its divisors is an integer number (442013372).

Almost surely, 2^1326040113 is an apocalyptic number.

It is an amenable number.

1326040113 is a deficient number, since it is larger than the sum of its proper divisors (442013375).

1326040113 is an equidigital number, since it uses as much as digits as its factorization.

1326040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 442013374.

The product of its (nonzero) digits is 432, while the sum is 21.

The square root of 1326040113 is about 36414.8336945262. The cubic root of 1326040113 is about 1098.6319392045.

Adding to 1326040113 its reverse (3110406231), we get a palindrome (4436446344).

The spelling of 1326040113 in words is "one billion, three hundred twenty-six million, forty thousand, one hundred thirteen".