Base | Representation |
---|---|
bin | 1100000011111011001011… |
… | …0110000000110001000001 |
3 | 1201221210102020100012022110 |
4 | 3000332302312000301001 |
5 | 3214234141010433423 |
6 | 44112140104325533 |
7 | 2536054634511132 |
oct | 300766266006101 |
9 | 51853366305273 |
10 | 13261564546113 |
11 | 425321a504674 |
12 | 15a221b1738a9 |
13 | 752738905cb0 |
14 | 33bc126a1c89 |
15 | 17ee6c8a8193 |
hex | c0fb2d80c41 |
13261564546113 has 16 divisors (see below), whose sum is σ = 19283287627520. Its totient is φ = 8057659469184.
The previous prime is 13261564546067. The next prime is 13261564546127. The reversal of 13261564546113 is 31164546516231.
It is not a de Polignac number, because 13261564546113 - 217 = 13261564415041 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13261564546183) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2152149556 + ... + 2152155717.
It is an arithmetic number, because the mean of its divisors is an integer number (1205205476720).
Almost surely, 213261564546113 is an apocalyptic number.
13261564546113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13261564546113 is a deficient number, since it is larger than the sum of its proper divisors (6021723081407).
13261564546113 is a wasteful number, since it uses less digits than its factorization.
13261564546113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4304305368.
The product of its digits is 1555200, while the sum is 48.
The spelling of 13261564546113 in words is "thirteen trillion, two hundred sixty-one billion, five hundred sixty-four million, five hundred forty-six thousand, one hundred thirteen".
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