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13262666343441 = 34420888781147
BaseRepresentation
bin1100000011111111010010…
…0001000010010000010001
31201221220021000120022002220
43000333310201002100101
53214243420040442231
644112441303531253
72536124143601214
oct300776441022021
951856230508086
1013262666343441
114253735437279
1215a2488159b29
13752882c65a88
1433bcb8b4b77b
1517eed4496896
hexc0ff4842411

13262666343441 has 4 divisors (see below), whose sum is σ = 17683555124592. Its totient is φ = 8841777562292.

The previous prime is 13262666343419. The next prime is 13262666343457. The reversal of 13262666343441 is 14434366626231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13262666343441 - 29 = 13262666342929 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13262666343491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2210444390571 + ... + 2210444390576.

It is an arithmetic number, because the mean of its divisors is an integer number (4420888781148).

Almost surely, 213262666343441 is an apocalyptic number.

It is an amenable number.

13262666343441 is a deficient number, since it is larger than the sum of its proper divisors (4420888781151).

13262666343441 is an equidigital number, since it uses as much as digits as its factorization.

13262666343441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4420888781150.

The product of its digits is 8957952, while the sum is 51.

The spelling of 13262666343441 in words is "thirteen trillion, two hundred sixty-two billion, six hundred sixty-six million, three hundred forty-three thousand, four hundred forty-one".

Divisors: 1 3 4420888781147 13262666343441