Base | Representation |
---|---|
bin | 1100000100000101110000… |
… | …1111101101000000100001 |
3 | 1201222001202022020001001200 |
4 | 3001001130033231000201 |
5 | 3214311001044133213 |
6 | 44113330112151413 |
7 | 2536215235025220 |
oct | 301013417550041 |
9 | 51861668201050 |
10 | 13264406630433 |
11 | 4254448816692 |
12 | 15a2892b38569 |
13 | 752a9c6796aa |
14 | 33c001d1ccb7 |
15 | 180087157273 |
hex | c105c3ed021 |
13264406630433 has 12 divisors (see below), whose sum is σ = 21896798247168. Its totient is φ = 7579660931640.
The previous prime is 13264406630429. The next prime is 13264406630467. The reversal of 13264406630433 is 33403660446231.
13264406630433 is a `hidden beast` number, since 1 + 3 + 2 + 6 + 4 + 4 + 0 + 6 + 630 + 4 + 3 + 3 = 666.
It is not a de Polignac number, because 13264406630433 - 22 = 13264406630429 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13264406630413) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 105273068433 + ... + 105273068558.
It is an arithmetic number, because the mean of its divisors is an integer number (1824733187264).
Almost surely, 213264406630433 is an apocalyptic number.
It is an amenable number.
13264406630433 is a deficient number, since it is larger than the sum of its proper divisors (8632391616735).
13264406630433 is a wasteful number, since it uses less digits than its factorization.
13264406630433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 210546137004 (or 210546137001 counting only the distinct ones).
The product of its (nonzero) digits is 2239488, while the sum is 45.
The spelling of 13264406630433 in words is "thirteen trillion, two hundred sixty-four billion, four hundred six million, six hundred thirty thousand, four hundred thirty-three".
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