13265633133049 has 4 divisors (see below), whose sum is σ = 14471599781520. Its totient is φ = 12059666484580.

The previous prime is 13265633133023. The next prime is 13265633133119. The reversal of 13265633133049 is 94033133656231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13265633133049 - 2¹⁵ = 13265633100281 is a prime.

It is a super-3 number, since 3×13265633133049³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13265633132993 and 13265633133011.

It is not an unprimeable number, because it can be changed into a prime (13265633134049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 602983324219 + ... + 602983324240.

It is an arithmetic number, because the mean of its divisors is an integer number (3617899945380).

Almost surely, 2^{13265633133049} is an apocalyptic number.

It is an amenable number.

13265633133049 is a deficient number, since it is larger than the sum of its proper divisors (1205966648471).

13265633133049 is a wasteful number, since it uses less digits than its factorization.

13265633133049 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1205966648470.

The product of its (nonzero) digits is 3149280, while the sum is 49.

The spelling of 13265633133049 in words is "thirteen trillion, two hundred sixty-five billion, six hundred thirty-three million, one hundred thirty-three thousand, forty-nine".