Base | Representation |
---|---|
bin | 11110001010011010000000… |
… | …010100000010010010100001 |
3 | 122101200211122110012202121211 |
4 | 132022122000110002102201 |
5 | 114341421014213441121 |
6 | 1150045321031150121 |
7 | 36641055022446436 |
oct | 3612320024022241 |
9 | 571624573182554 |
10 | 132656512640161 |
11 | 392a53470455a4 |
12 | 12a65879815341 |
13 | 59035bc871ab3 |
14 | 24a8876557b8d |
15 | 1050a788d4ce1 |
hex | 78a6805024a1 |
132656512640161 has 4 divisors (see below), whose sum is σ = 136935754983424. Its totient is φ = 128377270296900.
The previous prime is 132656512640101. The next prime is 132656512640189. The reversal of 132656512640161 is 161046215656231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 132656512640161 - 27 = 132656512640033 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132656512640101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2139621171585 + ... + 2139621171646.
It is an arithmetic number, because the mean of its divisors is an integer number (34233938745856).
Almost surely, 2132656512640161 is an apocalyptic number.
It is an amenable number.
132656512640161 is a deficient number, since it is larger than the sum of its proper divisors (4279242343263).
132656512640161 is an equidigital number, since it uses as much as digits as its factorization.
132656512640161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4279242343262.
The product of its (nonzero) digits is 1555200, while the sum is 49.
The spelling of 132656512640161 in words is "one hundred thirty-two trillion, six hundred fifty-six billion, five hundred twelve million, six hundred forty thousand, one hundred sixty-one".
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