Base | Representation |
---|---|
bin | 11000101101100010… |
… | …10001110000100001 |
3 | 1021020121001021201101 |
4 | 30112301101300201 |
5 | 204132312342213 |
6 | 10032244034401 |
7 | 646523642326 |
oct | 142661216041 |
9 | 37217037641 |
10 | 13266918433 |
11 | 56989141aa |
12 | 26a3092a01 |
13 | 1335788cc2 |
14 | 8dbdaab4d |
15 | 529ac8bdd |
hex | 316c51c21 |
13266918433 has 4 divisors (see below), whose sum is σ = 13271888128. Its totient is φ = 13261948740.
The previous prime is 13266918419. The next prime is 13266918479. The reversal of 13266918433 is 33481966231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13266918433 - 29 = 13266917921 is a prime.
It is a super-2 number, since 2×132669184332 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13266918403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2480841 + ... + 2486182.
It is an arithmetic number, because the mean of its divisors is an integer number (3317972032).
Almost surely, 213266918433 is an apocalyptic number.
It is an amenable number.
13266918433 is a deficient number, since it is larger than the sum of its proper divisors (4969695).
13266918433 is an equidigital number, since it uses as much as digits as its factorization.
13266918433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4969694.
The product of its digits is 559872, while the sum is 46.
The spelling of 13266918433 in words is "thirteen billion, two hundred sixty-six million, nine hundred eighteen thousand, four hundred thirty-three".
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