Base | Representation |
---|---|
bin | 11000101101110001… |
… | …11011010110110011 |
3 | 1021020201211011121020 |
4 | 30112320323112303 |
5 | 204133321030302 |
6 | 10032355030523 |
7 | 646546664055 |
oct | 142670732663 |
9 | 37221734536 |
10 | 13268923827 |
11 | 5699a63955 |
12 | 26a389b443 |
13 | 133600ba23 |
14 | 8dc36d8d5 |
15 | 529d72ebc |
hex | 316e3b5b3 |
13268923827 has 16 divisors (see below), whose sum is σ = 18763201440. Its totient is φ = 8311997952.
The previous prime is 13268923823. The next prime is 13268923841. The reversal of 13268923827 is 72832986231.
It is not a de Polignac number, because 13268923827 - 22 = 13268923823 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a self number, because there is not a number n which added to its sum of digits gives 13268923827.
It is not an unprimeable number, because it can be changed into a prime (13268923823) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 180952 + ... + 243477.
It is an arithmetic number, because the mean of its divisors is an integer number (1172700090).
Almost surely, 213268923827 is an apocalyptic number.
13268923827 is a gapful number since it is divisible by the number (17) formed by its first and last digit.
13268923827 is a deficient number, since it is larger than the sum of its proper divisors (5494277613).
13268923827 is a wasteful number, since it uses less digits than its factorization.
13268923827 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 425062.
The product of its digits is 1741824, while the sum is 51.
The spelling of 13268923827 in words is "thirteen billion, two hundred sixty-eight million, nine hundred twenty-three thousand, eight hundred twenty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •