Base | Representation |
---|---|
bin | 11110001011101000100011… |
… | …000011011001101111100011 |
3 | 122101222220022212211122021001 |
4 | 132023220203003121233203 |
5 | 114344311223410011421 |
6 | 1150152145312412431 |
7 | 36650131640555362 |
oct | 3613504303315743 |
9 | 571886285748231 |
10 | 132740847344611 |
11 | 39328093863250 |
12 | 12a7a095247117 |
13 | 590b53ca5748c |
14 | 24ac996c917d9 |
15 | 1052d626e0691 |
hex | 78ba230d9be3 |
132740847344611 has 4 divisors (see below), whose sum is σ = 144808197103224. Its totient is φ = 120673497586000.
The previous prime is 132740847344561. The next prime is 132740847344627. The reversal of 132740847344611 is 116443748047231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132740847344611 - 235 = 132706487606243 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132740847344111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6033674879290 + ... + 6033674879311.
It is an arithmetic number, because the mean of its divisors is an integer number (36202049275806).
Almost surely, 2132740847344611 is an apocalyptic number.
132740847344611 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
132740847344611 is a deficient number, since it is larger than the sum of its proper divisors (12067349758613).
132740847344611 is a wasteful number, since it uses less digits than its factorization.
132740847344611 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12067349758612.
The product of its (nonzero) digits is 10838016, while the sum is 55.
The spelling of 132740847344611 in words is "one hundred thirty-two trillion, seven hundred forty billion, eight hundred forty-seven million, three hundred forty-four thousand, six hundred eleven".
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