Search a number
-
+
132742835412563 = 157845495766959
BaseRepresentation
bin11110001011101010011001…
…100011010001111001010011
3122102000002110102201221210102
4132023222121203101321103
5114344324311331200223
61150153114451523015
736650232131063015
oct3613523143217123
9572002412657712
10132742835412563
1139328a13aa0112
1212a7a54abb946b
13590b7988b474c
1424acb04d221b5
151052e2bee7928
hex78ba998d1e53

132742835412563 has 4 divisors (see below), whose sum is σ = 133588331179680. Its totient is φ = 131897339645448.

The previous prime is 132742835412527. The next prime is 132742835412637. The reversal of 132742835412563 is 365214538247231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132742835412563 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132742835412499 and 132742835412508.

It is not an unprimeable number, because it can be changed into a prime (132742835412463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 422747883323 + ... + 422747883636.

It is an arithmetic number, because the mean of its divisors is an integer number (33397082794920).

Almost surely, 2132742835412563 is an apocalyptic number.

132742835412563 is a deficient number, since it is larger than the sum of its proper divisors (845495767117).

132742835412563 is an equidigital number, since it uses as much as digits as its factorization.

132742835412563 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 845495767116.

The product of its digits is 29030400, while the sum is 56.

The spelling of 132742835412563 in words is "one hundred thirty-two trillion, seven hundred forty-two billion, eight hundred thirty-five million, four hundred twelve thousand, five hundred sixty-three".

Divisors: 1 157 845495766959 132742835412563