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1328028638969 = 1638147414963
BaseRepresentation
bin10011010100110100101…
…011001101111011111001
311200221212121011211122202
4103110310223031323321
5133224300312421334
62454030554355545
7164642534115104
oct23246453157371
94627777154582
101328028638969
114722395aa52a
1219546a12bbb5
1398303c31806
14483c3c7173b
152482994717e
hex13534acdef9

1328028638969 has 4 divisors (see below), whose sum is σ = 1336176054096. Its totient is φ = 1319881223844.

The previous prime is 1328028638957. The next prime is 1328028638977. The reversal of 1328028638969 is 9698368208231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1328028638969 - 24 = 1328028638953 is a prime.

It is a super-2 number, since 2×13280286389692 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1328028638939) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4073707319 + ... + 4073707644.

It is an arithmetic number, because the mean of its divisors is an integer number (334044013524).

Almost surely, 21328028638969 is an apocalyptic number.

It is an amenable number.

1328028638969 is a deficient number, since it is larger than the sum of its proper divisors (8147415127).

1328028638969 is an equidigital number, since it uses as much as digits as its factorization.

1328028638969 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8147415126.

The product of its (nonzero) digits is 53747712, while the sum is 65.

The spelling of 1328028638969 in words is "one trillion, three hundred twenty-eight billion, twenty-eight million, six hundred thirty-eight thousand, nine hundred sixty-nine".

Divisors: 1 163 8147414963 1328028638969