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1328035 = 5265607
BaseRepresentation
bin101000100001110100011
32111110201111
411010032203
5314444120
644244151
714200552
oct5041643
92443644
101328035
11827855
12540657
13376627
14267d99
151b375a
hex1443a3

1328035 has 4 divisors (see below), whose sum is σ = 1593648. Its totient is φ = 1062424.

The previous prime is 1328017. The next prime is 1328051. The reversal of 1328035 is 5308231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5308231 = 28318757.

It is a cyclic number.

It is not a de Polignac number, because 1328035 - 25 = 1328003 is a prime.

It is a super-2 number, since 2×13280352 = 3527353922450, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1327997 and 1328015.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 132799 + ... + 132808.

It is an arithmetic number, because the mean of its divisors is an integer number (398412).

21328035 is an apocalyptic number.

1328035 is a deficient number, since it is larger than the sum of its proper divisors (265613).

1328035 is an equidigital number, since it uses as much as digits as its factorization.

1328035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 265612.

The product of its (nonzero) digits is 720, while the sum is 22.

The square root of 1328035 is about 1152.4040090177. The cubic root of 1328035 is about 109.9182588323.

The spelling of 1328035 in words is "one million, three hundred twenty-eight thousand, thirty-five".

Divisors: 1 5 265607 1328035