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1330000101211 = 2357826091357
BaseRepresentation
bin10011010110101010001…
…011101111111101011011
311201010221222211111102211
4103112222023233331123
5133242320011214321
62454554341535551
7165042433221325
oct23265213577533
94633858744384
101330000101211
11473060425271
1219591a4145b7
13985594c6612
144852da1c615
15248e2a6e0e1
hex135aa2eff5b

1330000101211 has 4 divisors (see below), whose sum is σ = 1387826192592. Its totient is φ = 1272174009832.

The previous prime is 1330000101203. The next prime is 1330000101229. The reversal of 1330000101211 is 1121010000331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330000101211 - 23 = 1330000101203 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1330000101191 and 1330000101200.

It is not an unprimeable number, because it can be changed into a prime (1330000111211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28913045656 + ... + 28913045701.

It is an arithmetic number, because the mean of its divisors is an integer number (346956548148).

Almost surely, 21330000101211 is an apocalyptic number.

1330000101211 is a deficient number, since it is larger than the sum of its proper divisors (57826091381).

1330000101211 is an equidigital number, since it uses as much as digits as its factorization.

1330000101211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57826091380.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 1330000101211 its reverse (1121010000331), we get a palindrome (2451010101542).

The spelling of 1330000101211 in words is "one trillion, three hundred thirty billion, one hundred one thousand, two hundred eleven".

Divisors: 1 23 57826091357 1330000101211