13300013111323 has 4 divisors (see below), whose sum is σ = 13300652340720. Its totient is φ = 13299373881928.

The previous prime is 13300013111219. The next prime is 13300013111339. The reversal of 13300013111323 is 32311131000331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13300013111323 - 2²⁹ = 13299476240411 is a prime.

It is a super-2 number, since 2×13300013111323² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13300013111294 and 13300013111303.

It is not an unprimeable number, because it can be changed into a prime (13300013111923) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 319583488 + ... + 319625101.

It is an arithmetic number, because the mean of its divisors is an integer number (3325163085180).

Almost surely, 2^{13300013111323} is an apocalyptic number.

13300013111323 is a deficient number, since it is larger than the sum of its proper divisors (639229397).

13300013111323 is an equidigital number, since it uses as much as digits as its factorization.

13300013111323 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 639229396.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 13300013111323 its reverse (32311131000331), we get a palindrome (45611144111654).

The spelling of 13300013111323 in words is "thirteen trillion, three hundred billion, thirteen million, one hundred eleven thousand, three hundred twenty-three".